0.7t^2-2t-14=0

Solution for 0.7t^2-2t-14=0 equation:

0.7t^2-2t-14=0

a = 0.7; b = -2; c = -14;
Δ = b2-4ac
Δ = -22-4·0.7·(-14)
Δ = 43.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{43.2}}{2*0.7}=\frac{2-\sqrt{43.2}}{1.4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{43.2}}{2*0.7}=\frac{2+\sqrt{43.2}}{1.4}
$